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X^2-3X-7=(X+3)(X+5)
We move all terms to the left:
X^2-3X-7-((X+3)(X+5))=0
We multiply parentheses ..
X^2-((+X^2+5X+3X+15))-3X-7=0
We calculate terms in parentheses: -((+X^2+5X+3X+15)), so:We add all the numbers together, and all the variables
(+X^2+5X+3X+15)
We get rid of parentheses
X^2+5X+3X+15
We add all the numbers together, and all the variables
X^2+8X+15
Back to the equation:
-(X^2+8X+15)
X^2-3X-(X^2+8X+15)-7=0
We get rid of parentheses
X^2-X^2-3X-8X-15-7=0
We add all the numbers together, and all the variables
-11X-22=0
We move all terms containing X to the left, all other terms to the right
-11X=22
X=22/-11
X=-2
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